95=1.5*t^2

Solution for 95=1.5*t^2 equation:

95=1.5*t^2

We move all terms to the left:

95-(1.5*t^2)=0

We get rid of parentheses

-1.5*t^2+95=0

We add all the numbers together, and all the variables

-1.5t^2+95=0

a = -1.5; b = 0; c = +95;
Δ = b2-4ac
Δ = 02-4·(-1.5)·95
Δ = 570
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{570}}{2*-1.5}=\frac{0-\sqrt{570}}{-3}
=-\frac{\sqrt{}}{-3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{570}}{2*-1.5}=\frac{0+\sqrt{570}}{-3}
=\frac{\sqrt{}}{-3}
$